Question

At an orbital height of 400 km, find the orbital period of the satellite.

Answer 1

h = 400 × 10³ m, 

R = 6371 × 10³ m, 

v = 7616 × 10³ kms^-1.

Substituting the values, 

T = 2π(R+h)/v 

T = 6.28 × \(\frac{6771}{7616}\)

T = 5.583 × 10³s = 5583 . 

T ≈ 93 min