**Given**

Power = 60 W =\(\frac{60}{1000}\) =0.06 Kw

(∵ 1Kw = 1000 W).

Time (t) = 6 hours.

Now

Power = \(\frac{Energy\,Consumed}{Time\,taken}\)

⇒ Energy Consumed = Power × Time taken

= 0.06 × 6 = 0.36kWh

**Hence 0.36 unit of electricity is consumed by a bulb in one day.**