Given
Power = 60 W =\(\frac{60}{1000}\) =0.06 Kw
(∵ 1Kw = 1000 W).
Time (t) = 6 hours.
Now
Power = \(\frac{Energy\,Consumed}{Time\,taken}\)
⇒ Energy Consumed = Power × Time taken
= 0.06 × 6 = 0.36kWh
Hence 0.36 unit of electricity is consumed by a bulb in one day.