Given: m = 600kg, g = m/s2 d = 5000 m, R = 6400 km = 6.4 x 106 m
To find: Decrease in weight of body (dW)
Formula: gd = g [1- \(\frac{d}{R}\)]
Calculation: Weight of body on the earth surface,
W = mg = 600 x 9.8 = 5880 N
Since, Wd = mgd
From formula,
Wd = mg [1- \(\frac{d}{R}\)]
=5880 [1- \(\frac{5\times10^3}{6.4\times10^6}\)]
=5880 [\(\frac{6.4-0.005}{6.4}\)]
= {antilog{log(5880) + [log(6.395) - log(6.4)]}}
= {antilog[3.7694 + (0.8058 – 0.8062)]}
= {antilog(3.7694 + 1.9996)}
= {antilog(3.7690)}
∴ Wd = 5875 N
∴ Decrease in weight = W - Wd = 5880 – 5875
dW = 5 N
Decrease in weight is 5 N.