The roster form of sets P, Q and R are P = {2, 3, 4, 5, 6, 7, 8, 9, 10}, Q = {2, 4, 6, 8, 10} and R = {4, 6, 8, 9, 10, 12}
First, we find Q ∩ R = {4, 6, 8, 10}
Then, P – (Q ∩ R) = {2, 3, 5, 7, 9} … (1)
Next, P – Q = {3, 5, 7, 9} and
P – R = {2, 3, 5, 7}
And so, (P – Q) ∪ (P – Q) = {2, 3, 5, 7, 9} ... (2)
Hence from (1) and (2), it verified that P – (Q ∩ R) = (P – Q) ∪ (P – R)
Finding the elements of set Q
Given, x = 2n
n = 1 → x = 2(1) = 2
n = 2 → x = 2(2) = 4
n = 3 → x = 2(3) = 6
n = 4 → x = 2(4) = 8
n = 5 → x = 2(5) = 10
Therefore, x takes values such as 2, 4, 6, 8, 10