Question

From the given venn diagram. Find 

(i) A, 

(ii) B, 

(iii) A ∪ B 

(iv) A ∩ B also verify that n(A ∪ B) = n(A) + n(B) – n(A ∩ B)

Answer 1

(i) A = {a, b, d, e, g, h}

(ii) B = {b, c, e, f, h, i, j}

(iii) A ∪ B = {a, b, c, d, e, f, g, h, i, j}

(iv) A ∩ B = {b, e, h}

So, n(A) = 6, n(B) = 7, n(A ∪B) = 10, n(A ∩ B) = 3

Now, n(A) + n(B) – n(A ∩ B) = 6 + 7 – 3 = 10

Hence, n(A) + n(B) – n(A ∩ B) = n(A ∪ B)