If the function f : N → N is defined by f (x) = √x, then f(25) / f(16) +f(1) is equal to

Question

If the function f : N → N is defined by f (x) = \(\sqrt{x}\), then\(\frac{f(25)}{f(16)+f(1)}\) is equal to 

(a) \(\frac{5}{6}\)

(b) \(\frac{5}{7}\)

(c) \(\frac{5}{3}\)

(d) 1

Answer 1

Answer : (d) 1

f : R → R given by f (x) = \(\sqrt{x}\)

∴ \(\frac{f(25)}{f(16)+f(1)} = \frac{5}{4+1} = \frac{5}{5}\) = 1.