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Solve 2 sin θ cos θ = cos θ (0° < θ < 360°)

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The given equation may be written as: 

2 sin θ cos θ– cos θ = 0 

⇒ cos θ (2 sin θ – 1) = 0 

⇒ cos θ = 0  or  2 sin θ – 1 = 0 

⇒ θ = 90°, 270° | sin θ = \(\frac{1}{2}\) ⇒ θ = 30°, 150° 

 ∴  θ = 30°, 90°, 150° 270°.

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