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in Coordinate Geometry by (55.5k points)
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Find the area of the triangle whose vertices are ((a+1) (a+2), (a+2)), ((a+2) (a+3), (a+3)) and ((a, 3) (a+4), (a+4)).

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Given, A triangle whose vertices are A ((a+1)(a+2), (a+2))

B ((a+2)(a+3), (a+3)) and C = ((a+b)(a+4), (a+4)).

To find: Find the area of a triangle.

Common terms will be canceled out

= 1/2[2]

Hence, = 1 sq unit

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