Given: Points of the quadrilatreral A(-3, -1), B(2, -1), C(1, 1), and D(-2, 1).
To Prove: ABCD is a trapezium
Proof:
For proving ABCD to be a trapezium, we need to prove that two of the sides are parallel.
Therefore, AB and CD are parallel.
For proving ABCD a trapezium,
Slope of AB = Slope of CD
Slope of AB = (-1 + 1)/(2 + 5) = 0
Slope of CD = (1 - 1)/(-2 - 1) = 0
Hence, the quadrilateral is a trapezium.
