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What is de Broglie wavelength of an electron accelerated through 25000 volt?

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Given: V = 25000 volt

To find: De-broglie wavelength (λ)

Formula: λ =  \(\frac{12.27}{\sqrt V}\) Å

Calculation: Using formula,

λ = \(\frac{12.27}{\sqrt {25000}}\) x 10-10 

Ans: The de-broglie wavelength of electron is 0.0776 x 10–10 m.

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