Question

Draw a right triangle in which the sides (other than hypotenuse) are of lengths 2.2 cm and 2.2 cm. Then construct another triangle whose sides are 5/3 times the corresponding sides of the given triangle.

Answer 1

Step1: Construct a segment AB of 2.2 cm

Step2: Construct AC of 2.2 cm at 90°. Join B and C to get right-angled triangle ABC

Step3: Draw a ray at any angle from point A below AB

Step4: Take any distance in compass and keeping the needle of the compass on point A cut an arc on ray constructed in step3 and name that point X₁. Keeping the distance in compass same keep the needle of the compass on point X₁ and cut an arc on the same ray and mark that point as X₂. Draw 5 such parts (greater of 5 and 3 in 5/3), i.e. by repeating this process mark points upto X₅

Step5: Join X₃ and B (3 being smaller of 5 and 3 in 5/3 and not X₅ because the ratio 5/3 is greater than 1)

Step6: Now extend AB and draw a line parallel to X₃B from X₅ intersecting AB at D

Step7: Extend AC and draw a line parallel to BC from point D intersecting AC at E and ΔADE whose sides are 5/3 times ΔABC is ready