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There are two circles intersecting each other. Another smaller circle with center O, is lying between the common region of the two larger circles. Centers of the circle (i.e., A, O and B) are lying on a straight line. AB = 16 cm and the radii of the larger circles are 10 cm each. What is the area of the smaller circle?

(a) 4π cm

(b) 2π cm

(c) \(\frac{4}{π}\) cm

(d) \(\frac{π}{4}\) cm2

1 Answer

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Answer : (a) 4π cm2 

Given figure: 

AB = 16 cm 

AQ = 10 cm

AO = \(\frac{AB}{2}\) = 8 cm

∴ OQ = AQ – AO = 10 cm – 8 cm = 2 cm

∴ Area of smaller circle with centre O = π × (2)2 

= 4π cm2

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