Let the two numbers be x, y
\(\frac{x}{y}=\frac{5}{6}\)
⇒ 6x = 5y
6x – 5y = 0 … (1)
\(\frac{x-8}{y-8}=\frac{4}{5}\)
⇒ 5(x – 8) = 4(y – 8)
5x – 40 = 4y – 32
5x – 4y = 40 – 32
5x – 4y = 8 … (2)

Substitute y = 48 in (1)
6x – 5(48) = 0
6x – 240 = 0
6x = 240
x = \(\frac{240}{6}\) = 40
\(\frac{x}{y}=\frac{40}{48}=\frac{5}{6}\)
∴ The numbers are in the ratio 5 : 6