Question

X has twice as much money as that of Y and Y has 50% more money than that of Z. If the average money of all of them is Rs 110, then the money which X has 

(a) Rs 55 

(b) Rs 60 

(c) Rs 90 

(d) Rs 180

Answer 1

Answer is: (d) 60

Let Z have Rs X. Then, 

Y has 150% of Rs X = Rs \(\frac{150X}{100}=\frac{3X}{2}\) 

X hax  2 x Rs \(\frac{3X}{2} = Rs\, 3X\)

Given, \(\frac{X+\frac{3X}{2}+3X}{3}\) = 110

⇒ \(\frac{2X+3X+6X}{2}\) = 330

⇒ 11X = 660 ⇒ X = 60