LIVE Course for free

Rated by 1 million+ students
Get app now
0 votes
5.9k views
in Number System by (48.5k points)
closed by

The average age of a father and his two sons is 27 years. Five years ago, the average age of the two sons was 12 years. If the difference between the ages of two sons is 4 years, then the present age of the father is 

(a) 34 years 

(b) 47 years 

(c) 64 years 

(d) 27 years

1 Answer

+1 vote
by (51.1k points)
selected by
 
Best answer

Answer is: (b) 47 years.

Let the ages of father and his two sons be x, y and z years respectively. 

Given, x + y + z = 3 × 27 = 81      … (i) 

and (y – 5) + (z – 5) = 2 × 12 ⇒ y + z = 34   … (ii) 

From (i) and (ii) 

Age of father (x) = 81 – 34 = 47 years.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...