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In an examination, a pupil’s average marks were 63 per paper. If he had obtained 20 more marks for his Geography paper and 2 more marks for his History paper, his average per paper would have been 65. How many papers were there in the examination ?

(a) 8 

(b) 9 

(c) 10 

(d) 11

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Answer is: (d) 11.

Let there be n papers in all. 

Total marks originally for n papers = 63n 

Total marks with increased average = 65n 

Given, 65n – 63n = 20 + 2 ⇒ 2n = 22 ⇒ n = 11.

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