Answer is: (b) 17 years 7 months
Let the average age of 11 players be x.
Then, total age of 11 players = 11x
Total age of 9 players = 11x – (17 + 20) = 11x – 37
Let y be the total age of the 2 new players.
Then \(\frac{11x-37+y}{11}=x - \frac{1}{6} = \frac{6x-1}{6}\)
⇒ 66x – 222 + 6y = 66x – 11
⇒ 6y = –11 + 222 = 211 ⇒ y = \(\frac{211}{6}\) years
∴ Average age of the two players = \(\frac{y}{2}\) = \(\frac{211}{12}\) = 17 years 7 months