Question

Of the four numbers, the first is twice the second, the second is one-third of the third and third is 5 times the fourth. The average of the numbers is 24.75. The largest of these numbers is 

(a) 9 

(b) 25 

(c) 30 

(d) 45

Answer 1

Answer is: (d)

Let the fourth number be x. Then, 

Third number = 5x 

Second number = \(\frac{5x}{3}\)

First number = \(\frac{10x}{3}\)

∴ x + 5x + \(\frac{5x}{3}\) + \(\frac{10x}{3}\) = (24.75 × 4) = 99

⇒ 3x + 15x + 5x + 10x = 99 × 3

⇒ 33x = 99 × 3 ⇒ x = \(\frac{99\times3}{33}\)= 9 

∴ The numbers are 9, 45, 15, 30

⇒ Largest number = 45