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in Physics by (30.0k points)

A submarine emits a sonar pulse, which returns from an underwater cliff in 1.02 s. If the speed of sound in salt water is 1531 m/s, how far away is the cliff?

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t = 1.02 s, v = 1531 m/s 

distance d = v × t = 1531×1.022 m = 780.81 m

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