Answer : (c) 46 \(\frac{1}{3}\) cm
∴ Required perimeter = AB + arc length BC + CD + arc length DE + AE
= 14 + \(\frac{60}{360}\) × 2 × \(\frac{22}{7}\) × 14+ 7 + \(\frac{30}{360}\) × 2 × \(\frac{22}{7}\) × 7 + 7
= 28 + \(\frac{44}{3}\) + \(\frac{11}{3}\)
= 28 + \(\frac{55}{3}\)
= \(\frac{139}{3}\)
= 46 \(\frac{1}{3}\) cm