Given: Radius of the circle = OA =OB = 21cm
and θ = 60°
(i) Length of the arc
= 22cm
(ii) Area of the sector formed by this arc
= 11 × 21
= 231 cm2
(iii) area of the segment formed by the corresponding chord of the arc
In ΔOAB,
∠OAB = ∠OBA (As OA = OB)
∠OAB + ∠AOB + ∠OBA = 180°
2∠OAB + 60° = 180°
∠OAB = 60°
∴ ΔOAB is an equilateral triangle.