Question

It is proposed to add to a square lawn with the side 58m, two circular ends (the centre of each circle being the point of intersection of the diagonals of the square.) Find the area of the whole lawn [Take π=3.14]

Answer 1

ABCD is a square lawn of side 58m. AED and BFC are two circular ends.

Now, diagonal of the lawn = √(58)² + (58)² = 58√2m

It is given that diagonal of square = Diameter of circle

∴The radius of a circle having a centre at the point of intersection of diagonal

It is given that square ABCD is inscribed by the circle with centre O.

∴Area of 4 segments = Area of circle – Area of square

= πr² – (side)²

= 5286.28 – 961.14

= 4325.14 m²