Question

In an equilateral triangle of side 12cm, a circle is inscribed touching its sides. Find the area of the portion of the triangle not included in the circle. [Take √3=1.73 and π=3.14]

Answer 1

= 36√3cm²

Now, we have to find the area of a circle. For that we need a radius.

Draw AD ⊥ BC

So, In BDO

⇒ r = 2√3cm

Now, Area of circle = πr²

= 3.14 × (2√3)²

= 37.68cm²

Area of shaded region = Area of ΔABC – Area of circle

= 36√3 – 37.68

= 36(1.73) – 37.68

= 24.6cm²

Hence, the area of the portion of the triangle not included in the circle is 24.6cm²