Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
910 views
in Surface Areas And Volumes by (44.5k points)
closed by

A decorative block as shown in the given figure is made of a cube and a hemisphere. The edge of the cube is 10cm, and the radius of the hemisphere attached on the top is 3.5. Find the cost of painting the block at the rate of 50 paise per sq.cm.

1 Answer

+1 vote
by (55.5k points)
selected by
 
Best answer

Given that side of a cube = 10cm

Total Surface Area of cube = 6(side)2

= 6 × 10 × 10

= 600cm2

Now, Radius of hemisphere = 3.5cm

Curved Surface Area of hemisphere = 2πr= 2 x 22/7 x 3.5 x 3.5

= 77cm2

Base area of hemisphere = Area of circle = πr2

= 22/7 x 3.5 x 3.5

= 38.5cm2

Therefore,

Total Surface Area of block = Total Surface area of a cube + CSA of the hemisphere - Base area of a hemisphere

= 600 + 77 – 38.5

= 638.5cm2

Cost of painting the block of 1cm2 = Rs 0.50

Cost of painting the block of 638.5cm2 = Rs 0.50 × 638.5

= Rs 319.25

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...