(i) b) 78.57m2
Cloth material required = 2 X S A of hemispherical dome
= 2 x 2πr2
= 2 x 2 x \(\frac{22}{7}\) x (2.5)2 m2
= 78.57 m2
(ii) a) πr2h
Volume of a cylindrical pillar = πr2h
(iii) b) = 123.2 m2
Lateral surface area = 2 x 2πrh
= 4 x \(\frac{22}{7}\) x 1.4 x 7 m2
= 123.2 m2
(iv) d) 89.83 m3
Volume of hemisphere = \(\frac{2}{3}\)πr3
= \(\frac{2}{3}\frac{22}{7}\) (3.5)3 m3
= 89.83 m3
(v) b) 1:8
Sum of the volumes of two hemispheres of radius 1cm each = 2 x \(\frac{2}{3}\pi1^3\)
Volume of sphere of radius 2cm = \(\frac{4}{3}\pi2^3\)
So, required ratio is \(\frac{2\times\frac{2}{3}\pi1^3}{\frac{4}{3}\pi2^3}\)
= 1:8