( 1+ C1/C0) (1+C2/C1) (1+ C3/C2)... (1+ Cn/Cn-1) is equal to

Question

\((1+ \frac{C_1}{C_0})\)\((1+ \frac{C_2}{C_1})\)\((1+ \frac{C_3}{C_2})\)...\((1+ \frac{C_n}{C_{n-1}})\) is equal to

(a) \(\frac{n+1}{n\,!}\)

(b) \(\frac{(n+1)^n}{(n-1)!}\)

(c) \(\frac{(n-1)^n}{n!}\)

(d) \(\frac{(n+1)^n}{n!}\)

Answer 1

Answer :  (d) \(\frac{(n+1)^n}{n!}\)