Greater diameter of the bucket = 30 cm
Radius of the bigger end of the bucket = R = 15 cm
Diameter of the smaller end of the bucket = 10 cm
Radius of the smaller end of the bucket = r = 5 cm
Height of the bucket = 24 cm
Slant height, l = √{h2 + (R – r)2}
= √{(24)2 +(15 – 5)2
= √576 + (10)2
= √576 + 100
= √676
= 26 cm
Now,
= 3.14 × 8 [225 + 25 + 75]
= 3.14 × 8 ×325
= 8164 cm3
= 8.164 Litres
A litre of milk cost Rs 20
So, total cost of filling the bucket with milk = Rs 20 × 8.164
= Rs 163.28
Surface Area of the bucket
= CSA of the frustum + Area of circular base
= πl(R+r) + πr2
= π [{26×(15+5)} + (5)2]
= π[520 + 25 ]
= 3.14 × 545
= 1711.3 cm2
Cost of 100cm2 of metal sheet = Rs 10
= Rs 171.13