If \(\begin{bmatrix}2&-1\\[0.3em]2&0\end{bmatrix}\)+2A =\(\begin{bmatrix}-3&5\\[0.3em]4&3\end{bmatrix},\) the matrix A equals
(a) \(\begin{bmatrix}-5&6\\[0.3em]2&3\end{bmatrix}\)
(b) \(\begin{bmatrix}-\frac52&3\\[0.3em]1&\frac32\end{bmatrix}\)
(c) \(\begin{bmatrix}-\frac52&6\\[0.3em]2&3\end{bmatrix}\)
(d) \(\begin{bmatrix}-5&8\\[0.3em]1&3\end{bmatrix}\)