(i) Let the points be A (2, 2) B (-2, -2) and C(-2√3, 2√3)
All the 3 sides of ∆ABC are equal,
Hence ∆ABC is an equilateral triangle.
(ii) Let the points be A (√3, 2), B (0, 1) and C (0, 3).
All the 3 sides of ∆ABC are equal.
Hence ∆ABC is an equilateral triangle.