Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
1.0k views
in Squares And Square Roots by (49.2k points)

Assume that \(\sqrt {13}\) = 3.605 (approx.) and \(\sqrt{130}\) = 11.40 (approx.). 

Find the value of \(\sqrt{1.3}\) + \(\sqrt {1300}\) + \(\sqrt {0.013}\) 

(a) 36.164 

(b) 37.304 

(c) 36.304 

(d) 37.164

Please log in or register to answer this question.

1 Answer

+1 vote
by (53.1k points)

(b) 37.304

\(\sqrt{1.3} +\sqrt{1300}+\sqrt{0.013}\)

\(\sqrt{\frac{130}{100}}\) + \(\sqrt{13\times100}\) + \(\sqrt{\frac{130}{10000}}\)

\({\frac{\sqrt{130}}{\sqrt{100}}}\) + \(\sqrt{13}\) x \(\sqrt{100}\) + \(\frac{\sqrt{130}}{\sqrt{10000}}\)

\(\frac{11.40}{10}\) + 3.605 x 10 + \(\frac{11.40}{100}\) 

= 1.14 + 36.05 + 0.114 = 37.304

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...