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A car travels at an uniform speed. At 2pm it is at a distance of 5 km at 6 pm it is at a distance of 120 km. Using section formula

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A car travels at an uniform speed. At 2pm it is at a distance of 5 km at 6 pm it is at a distance of 120 km. Using section formula, find at what distance it will reach 2 mid night.

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120 = \(\frac{8(50)+4(y)}{12}\)

1440 = 400 + 4y 

4y = 1040

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