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in Squares And Square Roots by (49.2k points)
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If \(\sqrt{1369}\) + \(\sqrt{0.0615+X}\) , =37.5, then x is equal to 

(a) 10–1 

(b) 10–2 

(c) 10–3 

(d) 10

1 Answer

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Best answer

(c) 10-3

\(\sqrt{1369} +\sqrt{0.0615+X}\) = 37.25

\(\Rightarrow\) \(\sqrt{0.0615+X}\) = 37.25 - \(\sqrt{1369}\)

= 37.25 - 37 = 0.25

\(\Rightarrow\) 0.0615 + x = (0.25)2 = 0.0625

\(\Rightarrow\) x = 0.0625 - 0.0615 = 0.001 = \(\frac{1}{10^3}\) = 10-3.

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