If a = 0.1039, then the value of √(4a^2 - 4a +1) +3a is (a) 0.1039 (b) 0.2078 (c) 1.1039 (d) 2.1039

Question

If a = 0.1039, then the value of \(\sqrt{4a^2- 4a +1}\) + 3a is

(a) 0.1039

(b) 0.2078

(c) 1.1039

(d) 2.1039

Answer 1

(c) 1.1039

\(\sqrt{4a^2-4a+1}+3a\)

= \(\sqrt{(1)^2-2\times 2a\times 1 +(2a)^2}+3a\)

= \(\sqrt{(1-2a)^2}+3a\) = (1 - 2a) + 3a = 1 + a

= 1 + 0.1039 = 1.1039.