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in Cubes And Cube Roots by (49.2k points)
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The smallest of \(\sqrt8 + \sqrt5\)\(\sqrt7+\sqrt6\) , \(\sqrt{10}+\sqrt3\) and \(\sqrt{11}+\sqrt2\)  is

(a) \(\sqrt8 + \sqrt5\)

(b) \(\sqrt7+\sqrt6\)

(c) \(\sqrt{10}+\sqrt3\)

(d) \(\sqrt{11}+\sqrt2\)

1 Answer

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Best answer

(d) \(\sqrt{11}+\sqrt2\)

\(\sqrt{8}+\sqrt5\) = 2.83 + 2.24 = 5.07

\(\sqrt{7}+\sqrt6\) = 2.65 + 2.45 = 5.09

\(\sqrt{10}+\sqrt{13}\) = 3.16 + 3.61 = 6.77

\(\sqrt{11}+\sqrt{2}\) = 3.32 + 1.41 = 4.73

\(\therefore\) Smallest is \(\sqrt{11}+\sqrt{2}\)

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