# If the lengths of the parallel sides of an isosceles trapezium are 20 cm and 30 cm and the area is 100 cm^2, then

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If the lengths of the parallel sides of an isosceles trapezium are 20 cm and 30 cm and the area is 100 cm2, then what is the length of the non-parallel sides ?

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Area of the trapezium = $\frac{1}{2}(AB + EF)$ x height

⇒ 100 = $\frac{1}{2}(20 + 30)$ x h ⇒ = 4 ⇒ AC = BD = 4 cm

∴ EA = BF = $\sqrt{AC^2 + EC^2}$ = $\sqrt{16 + 25}$ = $\sqrt{41}$ cm.