Area of field ABGFEA = Area of Δ ABC + Area of trapezium BCHG + Area of Δ GHF + Area of Δ FDE + Area of Δ DEA

\(=\frac{1}{2}\times40\times35\,+\)\(\frac{1}{2}\times(50\times35)\times50\,+\)\(\frac{1}{2}\times50\times50\,+\) \(\frac{1}{2}\times90\times45\,+\) \(\frac{1}{2}\times45\times50\)

= = 700 m^{2} + 2125 m^{2} + 1250 m^{2} + 2025 m^{2} + 1125 m^{2}

= 7225 m^{2}