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The side of a rhombus is 10 cm and one diagonal is 16 cm. The area of the rhombus is 

(a) 96 cm

(b) 95 cm

(c) 94 cm

(d) 93 cm

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(a) 96 cm2

Since the diagonals of a rhombus bisect each other at right angles. 

In Δ AOB, BO2\(\sqrt{AB^2-AO^2}\)

\(\sqrt{100-64}\) cm

\(\sqrt{36}\) = 6 cm 

∴ The other diagonal = 2 × 6 cm = 12 cm 

∴ Area of the rhombus = \(\frac12\) × 16 cm × 12 cm = 96 cm2.

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