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The perimeter of a rhombus is 40 cm. If the length of one of its diagonals be 12 m, then the length of the other diagonal is 

(a) 14 cm 

(b) 15 cm 

(c) 16 cm 

(d) 12 cm

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(c) 16 cm.

Each side of the rhombus = \(\frac{40\,cm}{4}\) = 10 cm

Length of the other diagonal = 2 × \(\sqrt{10^2-(\frac{12}{2})^2}\)

= 2 x \(\sqrt{100-36}\) = 2 x \(\sqrt{64}\) cm = 16 cm.

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