(b) \(\frac{3}{5}\)
Number of students getting marks equal to or more than 40 = 9 (44, 45, 46, 42, 48, 40, 43, 47, 44)
\(\therefore\) P(pass) = \(\frac{Number\,of\,students\,who\,passed}{Total\,number\,of\,students}\)
= \(\frac{9}{15}\) = \(\frac{3}{5}\)