(d) 684 m2
In right angle Δ ADC,
AC2 = AD2 + DC2
⇒ AC = \(\sqrt{24^2 + 32^2}\) = \(\sqrt{576+1024}\) = \(\sqrt{1600}\) = 40 m
∴ Area of the plot = Area of Δ ADC + Area of Δ ABC
For Δ ABC, S = \(\frac{25+25+40}{2}\) m = 45 m
∴ Required area = \(\frac12\) x 24m x 32m + \(\sqrt{45(45-25)(45-25)(45-40)}\) m2
= 384 m2 + \(\sqrt{45\times20\times20\times5}\) m2
= 384 m2 + 300 m2 = 684 m2.