In a single throw of two dice, what is the probability of getting a total of 11.(a) 1/9 (b) 1/18 (c) 1/12

Question

In a single throw of two dice, what is the probability of getting a total of 11.

(a) \(\frac{1}{9}\)

(b) \(\frac{1}{18}\)

(c) \(\frac{1}{12}\)

(d) \(\frac{35}{36}\)

Answer 1

(b) \(\frac{1}{18}\)

Total number of exhaustive cases = 6 × 6 = 36 A total of 11 may be obtained in 2 ways as (5, 6), (6, 5).

\(\therefore\) P (total of 11) = \(\frac{2}{36}\)=\(\frac{1}{18}\).