(b) \(\frac{18}{25}\)
S = { 1, 2, 3, 4, 5, .....49, 50}
Numbers containing digit 2 are 2, 12, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 32, 42, i.e., 14 in number.
Probability (Number contains 2) = \(\frac{14}{50}\) = \(\frac{7}{25}\)
\(\therefore\) Probability (Number does not contain 2)
= 1- \(\frac{7}{25}\) = \(\frac{18}{25}\)