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From a bag containing 60 standard and 40 substandard articles, two articles are chosen at random. What is the probability that one of them is standard and the other substandard?

(a) \(\frac{60}{100}\times \frac{40}{100}\)

(b) \(\frac{60}{100}\times \frac{39}{100}\)

(c) \(\frac{16}{33}\)

(d) 24%

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(c) \(\frac{16}{33}\)

Here two articles are chosen together without replacement 

P(one of the articles is substandard) = P (first article is standard) × P(second article is substandard) + P (first article is substandard) × P (second article is standard)

\(\frac{60}{100}\times\frac{40}{99}\) + \(\frac{40}{100}\times\frac{60}{99}\)

\(\frac{4800}{9900}\) = \(\frac{48}{99}\) = \(\frac{16}{33}\)

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