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In a Δ ABC right angled at B, it tan A = \(\frac{1}{\sqrt3}\), find the value of cos A cos C – sin A sin C. 

(a) 1 

(b) 0 

(c) –1 

(d) 2

1 Answer

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(b) 

Consider the Δ ABC in which ∠B = 90° 

Since, tan A = \(\frac{1}{\sqrt3}\)

∴ \(\frac{1}{\sqrt3}\) = \(\frac{BC}{AB}\)

⇒ \(\frac{AB}{\sqrt3}\) = \(\frac{BC}{1}\) = k

⇒ AB = √3k and BC = k

By Pythagoras’ Theorem, 

AC2 = AB2 + BC2 

= (√3 k)2 + k2 + 4k2 

⇒ AC = 2k

Now for ∠A, Base = AB, Perp. = BC, Hyp.= AC

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