(d) \(\frac{x^2}{18}\) m2
Let the breadth of the rectangular field be a m. Then, its length = 2a m
Given, 2(2a + a) = x ⇒ 6a = x ⇒ a = \(\frac{x}{6}\) m
∴ Length = 2a = 2 x \(\frac{x}{6}\) = \(\frac{x}{3}\) m
∴ Area of the rectangular field = \(\frac{x}{3}\) x \(\frac{x}{6}\) = \(\frac{x^2}{18}\) m2