(d) r < p
Perimeter of the rectangle ABCD = 2 (AB + AD) + (DC + CB) … (i)
Perimeter of parallelogram ABFE = 2 (AB + AE ) + (EF + FB) … (ii)
In right angled ΔADE, AE is the hypotenuse and the hypotenuse being the longest side in a Δ,
AE > AD ⇒ BF > BC
Also, AB = DC and AB = EF ⇒ DC = EF.
∴ From (i) and (ii)
Perimeter of rectangle < Perimeter of parallelogram.