Given exp. = (102)\(\frac12\) x \((\frac{1}{1000})^\frac13-(\frac{16}{1000})^\frac14\times3^0+(\frac54)^{-1}\)
= 102 x \(\frac12\) x \((\frac{1}{10})^{3\times\frac13} - (\frac{2}{10})^{4\times\frac14}\times3^0+\frac45\)
= 10 x \(\frac{1}{10}-\frac15+\frac45\) = 10 × 0.1 – 0.2 + 0.8 = 1 + 0.6 = 1.6.