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Given that 100.48 = x and 100.70 = y and xz = y2 , then find the approximate value of z ?

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Given, xz = y⇒ (100.48)z ⇒ (100.70)2

⇒ 100.48z = 101.40 ⇒ 0.48z = 1.40 ⇒ z = \(\frac{140}{48} = \) 2.9 (approx)

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