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\((64)^{\frac{-2}{3}}\times(\frac14)^{-3}\) equals

(a) \(\frac14\)

(b) 1 

(c) 4 

(d) 16

1 Answer

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Best answer

(c) 4
\((64)^{\frac{-2}{3}}\times(\frac14)^{-3}\) = \((4^3)^{\frac{-2}{3}}\times(4^{-1})^{-3}\)

= 4-2 x 43 = 4-2+3 = 41 = 4

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